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10x^2+5x-75=0
a = 10; b = 5; c = -75;
Δ = b2-4ac
Δ = 52-4·10·(-75)
Δ = 3025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3025}=55$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-55}{2*10}=\frac{-60}{20} =-3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+55}{2*10}=\frac{50}{20} =2+1/2 $
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